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Angle ACB with AB equal to CD

High school · ●●●○○ 50 pts

In triangle ABCABC, point DD lies on BCBC such that ∠BAD=60∘\angle BAD = 60^\circ, ∠B=20∘\angle B = 20^\circ and AB=CDAB = CD. Find ∠ACB\angle ACB in degrees.

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triangle angleslaw of sinesisosceles triangles