Mathegoras

Calculus › Extrema and curve sketching › Bounds from derivatives

Minimum of f(m) + f'(n) on an interval

High school · ●●○○○ 20 pts

The function f(x)=−x3+ax2−4f(x) = -x^3 + ax^2 - 4 has a local extremum at x=2x = 2. For m,n∈[−1,1]m, n \in [-1,1], find the minimum value of f(m)+f′(n)f(m) + f'(n), where f′f' is the derivative of ff.

Sign in to save your progress.

derivativesquadratic functions