Mean, spread and 90th percentile of heights

High school · ●●○○○ 20 pts

For women athletes at UCLA, heights are approximately normal. The 25th percentile height is

62.5

inches and the 75th percentile height is

65.5

inches. Using

z=\pm 0.67

for these quartiles, find the mean

\mu

and the standard deviation

\sigma

of the heights. Then, using

z=1.28

for the 90th percentile, find the 90th percentile height. Round

\sigma

and the 90th percentile height to two decimal places.