Search problems

7 problems match “telescoping sums”. Clear

Visitors search a sample. Sign in for free to search every problem. Sign in

  1. Difference of a linear function ●○○○○ 10 ptsThe function ff is linear and satisfies f(d+1)−f(d)=3f(d+1)-f(d) = 3 for all real numbers dd. What is f(3)−f(5)f(3)-f(5)?
  2. Sum after repeated difference insertion ●●○○○ 20 ptsWrite the 4 numbers 1,9,8,81,9,8,8 in a row and perform the following operation: for each pair of adjacent numbers, subtract the left number from the right number, and write the result between the two numbers. This completes one operation. Then perform the same operation on the 7 numbers now in a row, and continue this process for a total of 100 operations. Find the sum of the final row of numbers.
  3. Telescoping sum of odd-numerator fractions ●●○○○ 20 ptsCalculate 34+536+7144+9400+11900+131764+153136\frac{3}{4}+\frac{5}{36}+\frac{7}{144}+\frac{9}{400}+\frac{11}{900}+\frac{13}{1764}+\frac{15}{3136}. Give your answer as a decimal.
  4. Nested fraction sum with halving ●●○○○ 20 ptsDetermine the value of 2002+12(2001+12(2000+⋯+12(3+12⋅2))⋯ )2002+\frac{1}{2}\left(2001+\frac{1}{2}\left(2000+\cdots+\frac{1}{2}\left(3+\frac{1}{2}\cdot 2\right)\right)\cdots\right).
  5. Ratio of weighted harmonic sums ●●●○○ 50 ptsDetermine the value of 20161+20152+20143+⋯+1201612+13+14+⋯+12017\frac{\frac{2016}{1} + \frac{2015}{2} + \frac{2014}{3} + \dots + \frac{1}{2016}}{\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \dots + \frac{1}{2017}}.
  6. Nested half-fraction sum ●●●○○ 50 ptsFind the value of 2002+12(2001+12(2000+⋯+12(3+12⋅2))⋯ )2002 + \frac{1}{2} \left( 2001 + \frac{1}{2} \left( 2000 + \dots + \frac{1}{2} \left( 3 + \frac{1}{2} \cdot 2 \right) \right) \dotsb \right).
  7. Alternating-parity sum of reciprocal squares ●●●○○ 50 ptsCompute the value of 1+132+152+172+⋯+19972+19992−110022−110042−110062−⋯−119982−1200021+122+132+142+⋯+19992+110002\frac{1+\frac{1}{3^2}+\frac{1}{5^2}+\frac{1}{7^2}+\cdots+\frac{1}{997^2}+\frac{1}{999^2}-\frac{1}{1002^2}-\frac{1}{1004^2}-\frac{1}{1006^2}-\cdots-\frac{1}{1998^2}-\frac{1}{2000^2}}{1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\cdots+\frac{1}{999^2}+\frac{1}{1000^2}} without using a calculator. Give your answer as a decimal.