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Alternating sums

Solve the first problem 18 problems

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  1. Alternating sum of powers of negative one ●○○○○ 10 ptsFind (−1)−10+(−1)−9+(−1)−8+⋯+(−1)9+(−1)10(-1)^{-10} + (-1)^{-9} + (-1)^{-8} + \cdots + (-1)^9 + (-1)^{10}. (The sum has 21 terms, one for each integer exponent from −10-10 to 1010.)
  2. Alternating sum of consecutive integers ●○○○○ 10 ptsWhat is the value of the expression 100−99+98−97+96−95+⋯+4−3+2−1100 - 99 + 98 - 97 + 96 - 95 + \cdots + 4 - 3 + 2 - 1?
  3. Alternating sum of integers up to 2007 ●○○○○ 10 ptsFind the value of 1−2+3−4+⋯+2005−2006+20071 - 2 + 3 - 4 + \cdots + 2005 - 2006 + 2007.
  4. Alternating sum of a linear sequence ●●○○○ 20 ptsThe nnth term of a sequence is an=(−1)n+1(3n+2)a_n = (-1)^{n+1}(3n + 2). What is the value of a1+a2+⋯+a100a_1 + a_2 + \dots + a_{100}?
  5. Alternating block sum of squares ●●○○○ 20 ptsCompute 1002+992−982−972+962+952−942−932+…+42+32−22−12100^{2}+99^{2}-98^{2}-97^{2}+96^{2}+95^{2}-94^{2}-93^{2}+\ldots+4^{2}+3^{2}-2^{2}-1^{2}.
  6. Alternating sum in steps of four ●●○○○ 20 ptsFind the value of 2013−2009+2005−2001+⋯+29−252013-2009+2005-2001+\cdots+29-25.
  7. Sum of alternate terms of a sequence ●●●○○ 50 ptsA sequence consists of 2010 terms. Each term after the first is 1 larger than the previous term. The sum of the 2010 terms is 5307. When every second term is added up, starting with the first term and ending with the second last term, what is the sum?
  8. Counting alternating-parity increasing sequences ●●●○○ 50 ptsA finite strictly increasing sequence of integers is called alternating if its first term is odd, its second term is even, its third term is odd, and so on, alternating in parity. The empty sequence also counts as alternating. Let A(n)A(n) be the number of alternating sequences whose terms are all taken from {1,2,…,n}\{1,2,\ldots,n\}, so A(1)=2A(1)=2 and A(2)=3A(2)=3. Find A(20)A(20).
  9. Alternating sum of minimum values ●●●○○ 50 ptsFor a positive integer nn, define fn(x)=(∑i=1n∣x−i∣)2−∑i=1n(x−i)2f_n(x)=\left(\sum_{i=1}^{n}|x-i|\right)^2-\sum_{i=1}^{n}(x-i)^2 on the interval [0,n+1][0,n+1]. Let ana_n be the minimum value of fn(x)f_n(x). Find ∑n=111(−1)n+1an\sum_{n=1}^{11}(-1)^{n+1}a_n.

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