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Dot product

Solve the first problem 17 problems

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  1. Weighted inner product of a sum ●○○○○ 10 ptsLet ⟨u,v⟩=4u1v1+5u2v2\langle u,v\rangle = 4u_1v_1 + 5u_2v_2 for vectors u=(u1,u2)u=(u_1,u_2) and v=(v1,v2)v=(v_1,v_2) in R2\mathbb{R}^2. Given u=(3,−2)u=(3,-2), v=(4,5)v=(4,5) and w=(−1,6)w=(-1,6), find ⟨u+v,w⟩\langle u+v, w\rangle.
  2. Dot product with a linear combination ●○○○○ 10 ptsGiven that the angle between vectors a⃗\vec{a} and b⃗\vec{b} is 120∘120^{\circ}, and ∣a⃗∣=2|\vec{a}|=2, ∣b⃗∣=5|\vec{b}|=5, find (2a⃗−b⃗)⋅a⃗(2\vec{a}-\vec{b})\cdot\vec{a}.
  3. Triangle area from a dot product ●●○○○ 20 ptsIn triangle ABCABC, AB=1AB=1, BC=3BC=3, and AB→⋅BC→=−1\overrightarrow{AB}\cdot\overrightarrow{BC}=-1. Find the area of triangle ABCABC. Round to two decimal places.
  4. Dot product from norms and cross product ●●○○○ 20 ptsLet a\mathbf{a} and b\mathbf{b} be vectors such that ∥a∥=2,\|\mathbf{a}\| = 2, ∥b∥=5,\|\mathbf{b}\| = 5, and ∥a×b∥=8.\|\mathbf{a} \times \mathbf{b}\| = 8. Find ∣a⋅b∣.|\mathbf{a} \cdot \mathbf{b}|.
  5. Dot product with a cross product of differences ●●○○○ 20 ptsLet a=(−3101)\mathbf{a} = \begin{pmatrix} -3 \\ 10 \\ 1 \end{pmatrix}, b=(5π0)\mathbf{b} = \begin{pmatrix} 5 \\ \pi \\ 0 \end{pmatrix}, and c=(−2−27)\mathbf{c} = \begin{pmatrix} -2 \\ -2 \\ 7 \end{pmatrix}. Compute (a−b)⋅[(b−c)×(c−a)](\mathbf{a} - \mathbf{b}) \cdot [(\mathbf{b} - \mathbf{c}) \times (\mathbf{c} - \mathbf{a})].
  6. Dot product with a cross product of unit vectors ●●●○○ 50 ptsLet u\mathbf{u} and v\mathbf{v} be unit vectors, and let w\mathbf{w} be a vector such that u×v+u=w\mathbf{u} \times \mathbf{v} + \mathbf{u} = \mathbf{w} and w×u=v\mathbf{w} \times \mathbf{u} = \mathbf{v}. Compute u⋅(v×w)\mathbf{u} \cdot (\mathbf{v} \times \mathbf{w}).
  7. Dot product with circumcenter vector ●●●○○ 50 ptsIn triangle ABCABC, AB=3AB = 3 and AC=5AC = 5. Let OO be the circumcenter of triangle ABCABC. Find OA→⋅BC→\overrightarrow{OA} \cdot \overrightarrow{BC}.
  8. Side length from two dot products ●●●○○ 50 ptsIn △ABC\triangle ABC, AB→⋅AC→=AB→⋅CB→=4\overrightarrow{AB} \cdot \overrightarrow{AC} = \overrightarrow{AB} \cdot \overrightarrow{CB} = 4. Find the length of side ABAB. Round to two decimal places.

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